Base | Representation |
---|---|
bin | 100000110100110… |
… | …0011001111110000 |
3 | 2211202111111021120 |
4 | 1001221203033300 |
5 | 4223430130222 |
6 | 301143022240 |
7 | 36202561461 |
oct | 10151431760 |
9 | 2752444246 |
10 | 1101411312 |
11 | 515799691 |
12 | 268a3a980 |
13 | 147256191 |
14 | a63c8d68 |
15 | 66a6415c |
hex | 41a633f0 |
1101411312 has 80 divisors (see below), whose sum is σ = 2889457920. Its totient is φ = 361478656.
The previous prime is 1101411299. The next prime is 1101411341. The reversal of 1101411312 is 2131141011.
It is a super-2 number, since 2×11014113122 = 2426213756403122688, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1101411291 and 1101411300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1482013 + ... + 1482755.
It is an arithmetic number, because the mean of its divisors is an integer number (36118224).
Almost surely, 21101411312 is an apocalyptic number.
1101411312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1101411312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1444728960).
1101411312 is an abundant number, since it is smaller than the sum of its proper divisors (1788046608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1101411312 is a wasteful number, since it uses less digits than its factorization.
1101411312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1190 (or 1184 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
The square root of 1101411312 is about 33187.5174124248. The cubic root of 1101411312 is about 1032.7214023346.
Adding to 1101411312 its reverse (2131141011), we get a palindrome (3232552323).
The spelling of 1101411312 in words is "one billion, one hundred one million, four hundred eleven thousand, three hundred twelve".
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