Base | Representation |
---|---|
bin | 11001000010110001000101… |
… | …101011100111011000000111 |
3 | 112102222101222021222212201212 |
4 | 121002301011223213120013 |
5 | 103414023400430300012 |
6 | 1030130115224042035 |
7 | 32125306230223205 |
oct | 3102610553473007 |
9 | 472871867885655 |
10 | 110141310400007 |
11 | 32104738385247 |
12 | 1042a15a00331b |
13 | 495c3864a0073 |
14 | 1d2ac215da075 |
15 | cb00654cab22 |
hex | 642c45ae7607 |
110141310400007 has 2 divisors, whose sum is σ = 110141310400008. Its totient is φ = 110141310400006.
The previous prime is 110141310399979. The next prime is 110141310400117. The reversal of 110141310400007 is 700004013141011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110141310400007 - 28 = 110141310399751 is a prime.
It is a super-2 number, since 2×1101413104000072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110141310400307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55070655200003 + 55070655200004.
It is an arithmetic number, because the mean of its divisors is an integer number (55070655200004).
Almost surely, 2110141310400007 is an apocalyptic number.
110141310400007 is a deficient number, since it is larger than the sum of its proper divisors (1).
110141310400007 is an equidigital number, since it uses as much as digits as its factorization.
110141310400007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 110141310400007 its reverse (700004013141011), we get a palindrome (810145323541018).
The spelling of 110141310400007 in words is "one hundred ten trillion, one hundred forty-one billion, three hundred ten million, four hundred thousand, seven".
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