Base | Representation |
---|---|
bin | 1010000001000110111000… |
… | …0110010111101001001011 |
3 | 1102222221102120210021210221 |
4 | 2200101232012113221023 |
5 | 2420423431141413121 |
6 | 35231454431450511 |
7 | 2214513511300423 |
oct | 240215606275113 |
9 | 42887376707727 |
10 | 11014143310411 |
11 | 35670878403aa |
12 | 129a746386a37 |
13 | 61b82462bc97 |
14 | 2a1131ab5483 |
15 | 141783199b41 |
hex | a046e197a4b |
11014143310411 has 2 divisors, whose sum is σ = 11014143310412. Its totient is φ = 11014143310410.
The previous prime is 11014143310399. The next prime is 11014143310427. The reversal of 11014143310411 is 11401334141011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11014143310411 - 213 = 11014143302219 is a prime.
It is a super-2 number, since 2×110141433104112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11014143310451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507071655205 + 5507071655206.
It is an arithmetic number, because the mean of its divisors is an integer number (5507071655206).
Almost surely, 211014143310411 is an apocalyptic number.
11014143310411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014143310411 is an equidigital number, since it uses as much as digits as its factorization.
11014143310411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 11014143310411 its reverse (11401334141011), we get a palindrome (22415477451422).
The spelling of 11014143310411 in words is "eleven trillion, fourteen billion, one hundred forty-three million, three hundred ten thousand, four hundred eleven".
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