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11014205131 is a prime number
BaseRepresentation
bin10100100000111111…
…10110111011001011
31001102121011121000101
422100133312323023
5140024114031011
65020532350231
7536641125136
oct122037667313
931377147011
1011014205131
114742260376
122174775377
131066b5c257
14766b2b21d
15446e482c1
hex2907f6ecb

11014205131 has 2 divisors, whose sum is σ = 11014205132. Its totient is φ = 11014205130.

The previous prime is 11014205129. The next prime is 11014205143. The reversal of 11014205131 is 13150241011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11014205131 - 21 = 11014205129 is a prime.

It is a super-2 number, since 2×110142051312 (a number of 21 digits) contains 22 as substring.

Together with 11014205129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11014205099 and 11014205108.

It is not a weakly prime, because it can be changed into another prime (11014205101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507102565 + 5507102566.

It is an arithmetic number, because the mean of its divisors is an integer number (5507102566).

Almost surely, 211014205131 is an apocalyptic number.

11014205131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11014205131 is an equidigital number, since it uses as much as digits as its factorization.

11014205131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 11014205131 its reverse (13150241011), we get a palindrome (24164446142).

The spelling of 11014205131 in words is "eleven billion, fourteen million, two hundred five thousand, one hundred thirty-one".