Base | Representation |
---|---|
bin | 1010000001000111010010… |
… | …1100101000010011111101 |
3 | 1102222221201022002002010020 |
4 | 2200101310230220103331 |
5 | 2420424143011102303 |
6 | 35231513424202353 |
7 | 2214516324206601 |
oct | 240216454502375 |
9 | 42887638062106 |
10 | 11014254003453 |
11 | 3567134275758 |
12 | 129a7774693b9 |
13 | 61b84154791c |
14 | 2a114268b501 |
15 | 14178cc62a53 |
hex | a0474b284fd |
11014254003453 has 32 divisors (see below), whose sum is σ = 14755900377600. Its totient is φ = 7307814936576.
The previous prime is 11014254003367. The next prime is 11014254003499. The reversal of 11014254003453 is 35430045241011.
It is not a de Polignac number, because 11014254003453 - 220 = 11014252954877 is a prime.
It is a super-3 number, since 3×110142540034533 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11014254003353) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2114463513 + ... + 2114468721.
It is an arithmetic number, because the mean of its divisors is an integer number (461121886800).
Almost surely, 211014254003453 is an apocalyptic number.
It is an amenable number.
11014254003453 is a deficient number, since it is larger than the sum of its proper divisors (3741646374147).
11014254003453 is a wasteful number, since it uses less digits than its factorization.
11014254003453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9061.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 11014254003453 its reverse (35430045241011), we get a palindrome (46444299244464).
The spelling of 11014254003453 in words is "eleven trillion, fourteen billion, two hundred fifty-four million, three thousand, four hundred fifty-three".
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