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11014320193 is a prime number
BaseRepresentation
bin10100100001000000…
…10011000001000001
31001102121101102211221
422100200103001001
5140024131221233
65020535035041
7536642114452
oct122040230101
931377342757
1011014320193
114742329868
12217480ba81
131066b9c736
14766b5b129
15446e6c42d
hex290813041

11014320193 has 2 divisors, whose sum is σ = 11014320194. Its totient is φ = 11014320192.

The previous prime is 11014320169. The next prime is 11014320259. The reversal of 11014320193 is 39102341011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10431966769 + 582353424 = 102137^2 + 24132^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11014320193 is a prime.

It is not a weakly prime, because it can be changed into another prime (11014320113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507160096 + 5507160097.

It is an arithmetic number, because the mean of its divisors is an integer number (5507160097).

Almost surely, 211014320193 is an apocalyptic number.

It is an amenable number.

11014320193 is a deficient number, since it is larger than the sum of its proper divisors (1).

11014320193 is an equidigital number, since it uses as much as digits as its factorization.

11014320193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 11014320193 in words is "eleven billion, fourteen million, three hundred twenty thousand, one hundred ninety-three".