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110143431539 is a prime number
BaseRepresentation
bin110011010010100001…
…1110110001101110011
3101112022002022001110022
41212211003312031303
53301033204302124
6122333231554055
710646312502131
oct1464503661563
9345262261408
10110143431539
1142791106379
121941a98b92b
13a50413913b
14548c27c751
152ce99cac5e
hex19a50f6373

110143431539 has 2 divisors, whose sum is σ = 110143431540. Its totient is φ = 110143431538.

The previous prime is 110143431479. The next prime is 110143431569. The reversal of 110143431539 is 935134341011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110143431539 is a prime.

It is a super-2 number, since 2×1101434315392 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110143431499 and 110143431508.

It is not a weakly prime, because it can be changed into another prime (110143431569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55071715769 + 55071715770.

It is an arithmetic number, because the mean of its divisors is an integer number (55071715770).

Almost surely, 2110143431539 is an apocalyptic number.

110143431539 is a deficient number, since it is larger than the sum of its proper divisors (1).

110143431539 is an equidigital number, since it uses as much as digits as its factorization.

110143431539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 110143431539 in words is "one hundred ten billion, one hundred forty-three million, four hundred thirty-one thousand, five hundred thirty-nine".