Base | Representation |
---|---|
bin | 1010000001001000000000… |
… | …0010010101111000000011 |
3 | 1102222222012120001022202022 |
4 | 2200102000002111320003 |
5 | 2420430040211310413 |
6 | 35231544341512055 |
7 | 2214524124220301 |
oct | 240220002257003 |
9 | 42888176038668 |
10 | 11014444244483 |
11 | 35672216a2649 |
12 | 129a80b11262b |
13 | 61b871a95c94 |
14 | 2a115da4d271 |
15 | 14179e7e0608 |
hex | a0480095e03 |
11014444244483 has 2 divisors, whose sum is σ = 11014444244484. Its totient is φ = 11014444244482.
The previous prime is 11014444244359. The next prime is 11014444244491. The reversal of 11014444244483 is 38444244441011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11014444244483 - 240 = 9914932616707 is a prime.
It is a super-3 number, since 3×110144442444833 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11014444249483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507222122241 + 5507222122242.
It is an arithmetic number, because the mean of its divisors is an integer number (5507222122242).
Almost surely, 211014444244483 is an apocalyptic number.
11014444244483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014444244483 is an equidigital number, since it uses as much as digits as its factorization.
11014444244483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 786432, while the sum is 44.
Adding to 11014444244483 its reverse (38444244441011), we get a palindrome (49458688685494).
The spelling of 11014444244483 in words is "eleven trillion, fourteen billion, four hundred forty-four million, two hundred forty-four thousand, four hundred eighty-three".
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