Base | Representation |
---|---|
bin | 11001000010111001011001… |
… | …000010001010010110110011 |
3 | 112110000020222120102002121212 |
4 | 121002321121002022112303 |
5 | 103414200130100342042 |
6 | 1030134151555110335 |
7 | 32126043155201105 |
oct | 3102713102122663 |
9 | 473006876362555 |
10 | 110150225012147 |
11 | 321084a24552a1 |
12 | 1042ba275a23ab |
13 | 49601773547a8 |
14 | 1d2b429545575 |
15 | cb03d7e3c482 |
hex | 642e5908a5b3 |
110150225012147 has 2 divisors, whose sum is σ = 110150225012148. Its totient is φ = 110150225012146.
The previous prime is 110150225012083. The next prime is 110150225012203. The reversal of 110150225012147 is 741210522051011.
It is a strong prime.
It is an emirp because it is prime and its reverse (741210522051011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110150225012147 - 26 = 110150225012083 is a prime.
It is a super-2 number, since 2×1101502250121472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110150225092147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55075112506073 + 55075112506074.
It is an arithmetic number, because the mean of its divisors is an integer number (55075112506074).
Almost surely, 2110150225012147 is an apocalyptic number.
110150225012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110150225012147 is an equidigital number, since it uses as much as digits as its factorization.
110150225012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5600, while the sum is 32.
Adding to 110150225012147 its reverse (741210522051011), we get a palindrome (851360747063158).
The spelling of 110150225012147 in words is "one hundred ten trillion, one hundred fifty billion, two hundred twenty-five million, twelve thousand, one hundred forty-seven".
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