Base | Representation |
---|---|
bin | 1010000001010001010101… |
… | …1000111010000011010101 |
3 | 1110000012200012000010010101 |
4 | 2200110111120322003111 |
5 | 2421000203142340023 |
6 | 35233041132054101 |
7 | 2214643201413046 |
oct | 240242530720325 |
9 | 43005605003111 |
10 | 11016949965013 |
11 | 3568298053563 |
12 | 129b1aa304331 |
13 | 61bb80c49155 |
14 | 2a131a74c8cd |
15 | 14189979b1ad |
hex | a051563a0d5 |
11016949965013 has 2 divisors, whose sum is σ = 11016949965014. Its totient is φ = 11016949965012.
The previous prime is 11016949964989. The next prime is 11016949965023. The reversal of 11016949965013 is 31056994961011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10138002464529 + 878947500484 = 3184023^2 + 937522^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11016949965013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11016949965023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5508474982506 + 5508474982507.
It is an arithmetic number, because the mean of its divisors is an integer number (5508474982507).
Almost surely, 211016949965013 is an apocalyptic number.
It is an amenable number.
11016949965013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11016949965013 is an equidigital number, since it uses as much as digits as its factorization.
11016949965013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1574640, while the sum is 55.
The spelling of 11016949965013 in words is "eleven trillion, sixteen billion, nine hundred forty-nine million, nine hundred sixty-five thousand, thirteen".
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