Base | Representation |
---|---|
bin | 10000000010001011100… |
… | …001010100101110011111 |
3 | 10220100001222200020221120 |
4 | 100002023201110232133 |
5 | 121023043203141242 |
6 | 2202103424502023 |
7 | 142414633560165 |
oct | 20021341245637 |
9 | 3810058606846 |
10 | 1101852396447 |
11 | 395324a52950 |
12 | 15966817a913 |
13 | 7cb9a7b244a |
14 | 3b4894dd235 |
15 | 1d9dd4091ec |
hex | 1008b854b9f |
1101852396447 has 32 divisors (see below), whose sum is σ = 1615386240000. Its totient is φ = 662521856640.
The previous prime is 1101852396443. The next prime is 1101852396457. The reversal of 1101852396447 is 7446932581011.
It is not a de Polignac number, because 1101852396447 - 22 = 1101852396443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1101852396447.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1101852396443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1861929 + ... + 2381277.
It is an arithmetic number, because the mean of its divisors is an integer number (50480820000).
It is a 1-persistent number, because it is pandigital, but 2⋅1101852396447 = 2203704792894 is not.
Almost surely, 21101852396447 is an apocalyptic number.
1101852396447 is a deficient number, since it is larger than the sum of its proper divisors (513533843553).
1101852396447 is a wasteful number, since it uses less digits than its factorization.
1101852396447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 519871.
The product of its (nonzero) digits is 1451520, while the sum is 51.
The spelling of 1101852396447 in words is "one trillion, one hundred one billion, eight hundred fifty-two million, three hundred ninety-six thousand, four hundred forty-seven".
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