Base | Representation |
---|---|
bin | 1010000001011101001001… |
… | …0110011001011110111111 |
3 | 1110000111212010100210112122 |
4 | 2200113102112121132333 |
5 | 2421023201232414101 |
6 | 35234323501153155 |
7 | 2215114565110025 |
oct | 240272226313677 |
9 | 43014763323478 |
10 | 11020120201151 |
11 | 3569674617926 |
12 | 129b933b5b7bb |
13 | 61c267996319 |
14 | 2a153b7ca715 |
15 | 1419d2c6a51b |
hex | a05d25997bf |
11020120201151 has 2 divisors, whose sum is σ = 11020120201152. Its totient is φ = 11020120201150.
The previous prime is 11020120201147. The next prime is 11020120201247. The reversal of 11020120201151 is 15110202102011.
It is a weak prime.
It is an emirp because it is prime and its reverse (15110202102011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11020120201151 - 22 = 11020120201147 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11020140201151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510060100575 + 5510060100576.
It is an arithmetic number, because the mean of its divisors is an integer number (5510060100576).
Almost surely, 211020120201151 is an apocalyptic number.
11020120201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020120201151 is an equidigital number, since it uses as much as digits as its factorization.
11020120201151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 11020120201151 its reverse (15110202102011), we get a palindrome (26130322303162).
The spelling of 11020120201151 in words is "eleven trillion, twenty billion, one hundred twenty million, two hundred one thousand, one hundred fifty-one".
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