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1102012112083 is a prime number
BaseRepresentation
bin10000000010010101000…
…010100101110011010011
310220100111010012122121111
4100002111002211303103
5121023410100041313
62202131332034151
7142421613253351
oct20022502456323
93810433178544
101102012112083
113953a7120643
121596b1762957
137cbc490363c
143b4a27d67d1
151d9ec45743d
hex100950a5cd3

1102012112083 has 2 divisors, whose sum is σ = 1102012112084. Its totient is φ = 1102012112082.

The previous prime is 1102012112081. The next prime is 1102012112087. The reversal of 1102012112083 is 3802112102011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1102012112083 - 21 = 1102012112081 is a prime.

It is a super-3 number, since 3×11020121120833 (a number of 37 digits) contains 333 as substring.

Together with 1102012112081, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1102012112081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551006056041 + 551006056042.

It is an arithmetic number, because the mean of its divisors is an integer number (551006056042).

Almost surely, 21102012112083 is an apocalyptic number.

1102012112083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102012112083 is an equidigital number, since it uses as much as digits as its factorization.

1102012112083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 1102012112083 its reverse (3802112102011), we get a palindrome (4904124214094).

The spelling of 1102012112083 in words is "one trillion, one hundred two billion, twelve million, one hundred twelve thousand, eighty-three".