Base | Representation |
---|---|
bin | 10000000010010101000… |
… | …010100101110011010011 |
3 | 10220100111010012122121111 |
4 | 100002111002211303103 |
5 | 121023410100041313 |
6 | 2202131332034151 |
7 | 142421613253351 |
oct | 20022502456323 |
9 | 3810433178544 |
10 | 1102012112083 |
11 | 3953a7120643 |
12 | 1596b1762957 |
13 | 7cbc490363c |
14 | 3b4a27d67d1 |
15 | 1d9ec45743d |
hex | 100950a5cd3 |
1102012112083 has 2 divisors, whose sum is σ = 1102012112084. Its totient is φ = 1102012112082.
The previous prime is 1102012112081. The next prime is 1102012112087. The reversal of 1102012112083 is 3802112102011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1102012112083 - 21 = 1102012112081 is a prime.
It is a super-3 number, since 3×11020121120833 (a number of 37 digits) contains 333 as substring.
Together with 1102012112081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1102012112081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551006056041 + 551006056042.
It is an arithmetic number, because the mean of its divisors is an integer number (551006056042).
Almost surely, 21102012112083 is an apocalyptic number.
1102012112083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102012112083 is an equidigital number, since it uses as much as digits as its factorization.
1102012112083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 1102012112083 its reverse (3802112102011), we get a palindrome (4904124214094).
The spelling of 1102012112083 in words is "one trillion, one hundred two billion, twelve million, one hundred twelve thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •