Base | Representation |
---|---|
bin | 10000000010010101100… |
… | …110010100011000011001 |
3 | 10220100111202211111010002 |
4 | 100002111212110120121 |
5 | 121023414444243123 |
6 | 2202132304502345 |
7 | 142422056002106 |
oct | 20022546243031 |
9 | 3810452744102 |
10 | 1102021477913 |
11 | 3954014382a4 |
12 | 1596b491a9b5 |
13 | 7cbc6832655 |
14 | 3b4a3b53aad |
15 | 1d9ed1a7528 |
hex | 10095994619 |
1102021477913 has 2 divisors, whose sum is σ = 1102021477914. Its totient is φ = 1102021477912.
The previous prime is 1102021477897. The next prime is 1102021477967. The reversal of 1102021477913 is 3197741202011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 629121821584 + 472899656329 = 793172^2 + 687677^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102021477913 - 24 = 1102021477897 is a prime.
It is not a weakly prime, because it can be changed into another prime (1102021447913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551010738956 + 551010738957.
It is an arithmetic number, because the mean of its divisors is an integer number (551010738957).
Almost surely, 21102021477913 is an apocalyptic number.
It is an amenable number.
1102021477913 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102021477913 is an equidigital number, since it uses as much as digits as its factorization.
1102021477913 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21168, while the sum is 38.
Adding to 1102021477913 its reverse (3197741202011), we get a palindrome (4299762679924).
The spelling of 1102021477913 in words is "one trillion, one hundred two billion, twenty-one million, four hundred seventy-seven thousand, nine hundred thirteen".
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