Base | Representation |
---|---|
bin | 10000000010010101101… |
… | …100010001110010000101 |
3 | 10220100111212202212002002 |
4 | 100002111230101302011 |
5 | 121023420344241013 |
6 | 2202132402155045 |
7 | 142422105166511 |
oct | 20022554216205 |
9 | 3810455685062 |
10 | 1102023040133 |
11 | 395402304a94 |
12 | 1596b5352a85 |
13 | 7cbc6c5b742 |
14 | 3b4a403d141 |
15 | 1d9ed3b5358 |
hex | 10095b11c85 |
1102023040133 has 2 divisors, whose sum is σ = 1102023040134. Its totient is φ = 1102023040132.
The previous prime is 1102023040091. The next prime is 1102023040207. The reversal of 1102023040133 is 3310403202011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1083166807009 + 18856233124 = 1040753^2 + 137318^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102023040133 - 220 = 1102021991557 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102023043133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551011520066 + 551011520067.
It is an arithmetic number, because the mean of its divisors is an integer number (551011520067).
Almost surely, 21102023040133 is an apocalyptic number.
It is an amenable number.
1102023040133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102023040133 is an equidigital number, since it uses as much as digits as its factorization.
1102023040133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1102023040133 its reverse (3310403202011), we get a palindrome (4412426242144).
The spelling of 1102023040133 in words is "one trillion, one hundred two billion, twenty-three million, forty thousand, one hundred thirty-three".
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