Base | Representation |
---|---|
bin | 10000000010010110001… |
… | …011000100011101010111 |
3 | 10220100112102221221121222 |
4 | 100002112023010131113 |
5 | 121023424431041043 |
6 | 2202133251200555 |
7 | 142422233615642 |
oct | 20022613043527 |
9 | 3810472857558 |
10 | 1102031112023 |
11 | 395406918576 |
12 | 1596b7ba615b |
13 | 7cbc88267ca |
14 | 3b4a5140a59 |
15 | 1d9ede5bd68 |
hex | 100962c4757 |
1102031112023 has 2 divisors, whose sum is σ = 1102031112024. Its totient is φ = 1102031112022.
The previous prime is 1102031112001. The next prime is 1102031112031. The reversal of 1102031112023 is 3202111302011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1102031112023 - 28 = 1102031111767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1102031111992 and 1102031112010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102031111023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551015556011 + 551015556012.
It is an arithmetic number, because the mean of its divisors is an integer number (551015556012).
Almost surely, 21102031112023 is an apocalyptic number.
1102031112023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102031112023 is an equidigital number, since it uses as much as digits as its factorization.
1102031112023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1102031112023 its reverse (3202111302011), we get a palindrome (4304142414034).
The spelling of 1102031112023 in words is "one trillion, one hundred two billion, thirty-one million, one hundred twelve thousand, twenty-three".
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