Base | Representation |
---|---|
bin | 1010000001011110010101… |
… | …1011001001101001010111 |
3 | 1110000112200102112010210012 |
4 | 2200113211123021221113 |
5 | 2421024330143322403 |
6 | 35234415332150435 |
7 | 2215125532141265 |
oct | 240274533115127 |
9 | 43015612463705 |
10 | 11020440214103 |
11 | 3569819220341 |
12 | 129ba0316841b |
13 | 61c2b90803b8 |
14 | 2a156c0cd435 |
15 | 141a00dcded8 |
hex | a05e56c9a57 |
11020440214103 has 2 divisors, whose sum is σ = 11020440214104. Its totient is φ = 11020440214102.
The previous prime is 11020440214067. The next prime is 11020440214177. The reversal of 11020440214103 is 30141204402011.
11020440214103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11020440214103 - 28 = 11020440213847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11020440210103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510220107051 + 5510220107052.
It is an arithmetic number, because the mean of its divisors is an integer number (5510220107052).
Almost surely, 211020440214103 is an apocalyptic number.
11020440214103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11020440214103 is an equidigital number, since it uses as much as digits as its factorization.
11020440214103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11020440214103 its reverse (30141204402011), we get a palindrome (41161644616114).
The spelling of 11020440214103 in words is "eleven trillion, twenty billion, four hundred forty million, two hundred fourteen thousand, one hundred three".
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