Base | Representation |
---|---|
bin | 1010000001100000011011… |
… | …0011000001101101111011 |
3 | 1110000121010110002100221111 |
4 | 2200120012303001231323 |
5 | 2421032002012334321 |
6 | 35234551053021151 |
7 | 2215145441234443 |
oct | 240300663015573 |
9 | 43017113070844 |
10 | 11021000121211 |
11 | 3569a86284893 |
12 | 129bb3a7847b7 |
13 | 61c37807c092 |
14 | 2a15c25db123 |
15 | 141a3512c5e1 |
hex | a0606cc1b7b |
11021000121211 has 2 divisors, whose sum is σ = 11021000121212. Its totient is φ = 11021000121210.
The previous prime is 11021000121179. The next prime is 11021000121223. The reversal of 11021000121211 is 11212100012011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11021000121211 - 25 = 11021000121179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11021000121191 and 11021000121200.
It is not a weakly prime, because it can be changed into another prime (11021000121611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510500060605 + 5510500060606.
It is an arithmetic number, because the mean of its divisors is an integer number (5510500060606).
Almost surely, 211021000121211 is an apocalyptic number.
11021000121211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021000121211 is an equidigital number, since it uses as much as digits as its factorization.
11021000121211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 11021000121211 its reverse (11212100012011), we get a palindrome (22233100133222).
The spelling of 11021000121211 in words is "eleven trillion, twenty-one billion, one hundred twenty-one thousand, two hundred eleven".
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