Base | Representation |
---|---|
bin | 10100100001110011… |
… | …10100110010100011 |
3 | 1001110001222102110111 |
4 | 22100321310302203 |
5 | 140032334342011 |
6 | 5021334312151 |
7 | 540053025463 |
oct | 122071646243 |
9 | 31401872414 |
10 | 11021012131 |
11 | 474608a598 |
12 | 2176ab8657 |
13 | 10683a366c |
14 | 7679bdba3 |
15 | 447840121 |
hex | 290e74ca3 |
11021012131 has 2 divisors, whose sum is σ = 11021012132. Its totient is φ = 11021012130.
The previous prime is 11021012113. The next prime is 11021012159. The reversal of 11021012131 is 13121012011.
It is a happy number.
Together with previous prime (11021012113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11021012131 - 27 = 11021012003 is a prime.
It is a super-2 number, since 2×110210121312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11021012731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510506065 + 5510506066.
It is an arithmetic number, because the mean of its divisors is an integer number (5510506066).
Almost surely, 211021012131 is an apocalyptic number.
11021012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021012131 is an equidigital number, since it uses as much as digits as its factorization.
11021012131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11021012131 its reverse (13121012011), we get a palindrome (24142024142).
The spelling of 11021012131 in words is "eleven billion, twenty-one million, twelve thousand, one hundred thirty-one".
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