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1102102141319 is a prime number
BaseRepresentation
bin10000000010011010011…
…010000001100110000111
310220100201101121121111122
4100002122122001212013
5121024101122010234
62202144305424155
7142424055430304
oct20023232014607
93810641547448
101102102141319
11395442a21973
1215971793b05b
137cc0a46598a
143b4b07500ab
151da052dc92e
hex1009a681987

1102102141319 has 2 divisors, whose sum is σ = 1102102141320. Its totient is φ = 1102102141318.

The previous prime is 1102102141247. The next prime is 1102102141339. The reversal of 1102102141319 is 9131412012011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1102102141319 is a prime.

It is a super-2 number, since 2×11021021413192 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1102102141339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551051070659 + 551051070660.

It is an arithmetic number, because the mean of its divisors is an integer number (551051070660).

Almost surely, 21102102141319 is an apocalyptic number.

1102102141319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102102141319 is an equidigital number, since it uses as much as digits as its factorization.

1102102141319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 26.

It can be divided in two parts, 1102102 and 141319, that added together give a palindrome (1243421).

The spelling of 1102102141319 in words is "one trillion, one hundred two billion, one hundred two million, one hundred forty-one thousand, three hundred nineteen".