Base | Representation |
---|---|
bin | 1010000001100000110011… |
… | …0111101111011001010111 |
3 | 1110000121101112211101001111 |
4 | 2200120030313233121113 |
5 | 2421032204104121213 |
6 | 35235005133035451 |
7 | 2215151116326133 |
oct | 240301467573127 |
9 | 43017345741044 |
10 | 11021102020183 |
11 | 356a028853012 |
12 | 129bb68925b87 |
13 | 61c393209028 |
14 | 2a15d1d643c3 |
15 | 141a3e059a3d |
hex | a060cdef657 |
11021102020183 has 2 divisors, whose sum is σ = 11021102020184. Its totient is φ = 11021102020182.
The previous prime is 11021102020157. The next prime is 11021102020237. The reversal of 11021102020183 is 38102020112011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11021102020183 - 25 = 11021102020151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11021102020133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510551010091 + 5510551010092.
It is an arithmetic number, because the mean of its divisors is an integer number (5510551010092).
Almost surely, 211021102020183 is an apocalyptic number.
11021102020183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021102020183 is an equidigital number, since it uses as much as digits as its factorization.
11021102020183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 11021102020183 its reverse (38102020112011), we get a palindrome (49123122132194).
The spelling of 11021102020183 in words is "eleven trillion, twenty-one billion, one hundred two million, twenty thousand, one hundred eighty-three".
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