Search a number
-
+
11021120113 is a prime number
BaseRepresentation
bin10100100001110100…
…01111001001110001
31001110002011220120211
422100322033021301
5140032401320423
65021340504121
7540053655343
oct122072171161
931402156524
1011021120113
114746153733
122176b4b041
131068410863
14767a0b293
1544786210d
hex290e8f271

11021120113 has 2 divisors, whose sum is σ = 11021120114. Its totient is φ = 11021120112.

The previous prime is 11021120083. The next prime is 11021120119. The reversal of 11021120113 is 31102112011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10852847329 + 168272784 = 104177^2 + 12972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11021120113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11021120093 and 11021120102.

It is not a weakly prime, because it can be changed into another prime (11021120119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510560056 + 5510560057.

It is an arithmetic number, because the mean of its divisors is an integer number (5510560057).

Almost surely, 211021120113 is an apocalyptic number.

It is an amenable number.

11021120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11021120113 is an equidigital number, since it uses as much as digits as its factorization.

11021120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11021120113 its reverse (31102112011), we get a palindrome (42123232124).

It can be divided in two parts, 1102112011 and 3, that multiplied together give a palindrome (3306336033).

The spelling of 11021120113 in words is "eleven billion, twenty-one million, one hundred twenty thousand, one hundred thirteen".