Base | Representation |
---|---|
bin | 1010000001100001101001… |
… | …1111010100110110101011 |
3 | 1110000121222110202101212021 |
4 | 2200120122133110312223 |
5 | 2421033141102013120 |
6 | 35235043534125311 |
7 | 2215156562354101 |
oct | 240303237246653 |
9 | 43017873671767 |
10 | 11021330501035 |
11 | 356a135819068 |
12 | 12a0011350837 |
13 | 61c3cb6559ba |
14 | 2a161443bc71 |
15 | 141a5413caaa |
hex | a061a7d4dab |
11021330501035 has 32 divisors (see below), whose sum is σ = 13581047450880. Its totient is φ = 8582934297600.
The previous prime is 11021330501003. The next prime is 11021330501039. The reversal of 11021330501035 is 53010503312011.
11021330501035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11021330501035 - 25 = 11021330501003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11021330501039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20406351 + ... + 20939479.
It is an arithmetic number, because the mean of its divisors is an integer number (424407732840).
Almost surely, 211021330501035 is an apocalyptic number.
11021330501035 is a deficient number, since it is larger than the sum of its proper divisors (2559716949845).
11021330501035 is a wasteful number, since it uses less digits than its factorization.
11021330501035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 533799.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 11021330501035 its reverse (53010503312011), we get a palindrome (64031833813046).
The spelling of 11021330501035 in words is "eleven trillion, twenty-one billion, three hundred thirty million, five hundred one thousand, thirty-five".
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