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110214132433441 is a prime number
BaseRepresentation
bin11001000011110100111010…
…001101101000001000100001
3112110020100221101111110201021
4121003310322031220020201
5103421222020400332231
61030223401245005441
732133464642256451
oct3103647215501041
9473210841443637
10110214132433441
1132132607533853
12104402a1b53881
1349661c048a78a
141d3056cd2dd61
15cb1dc8729811
hex643d3a368221

110214132433441 has 2 divisors, whose sum is σ = 110214132433442. Its totient is φ = 110214132433440.

The previous prime is 110214132433423. The next prime is 110214132433487. The reversal of 110214132433441 is 144334231412011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110210943459600 + 3188973841 = 10498140^2 + 56471^2 .

It is a cyclic number.

It is not a de Polignac number, because 110214132433441 - 25 = 110214132433409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110214132433397 and 110214132433406.

It is not a weakly prime, because it can be changed into another prime (110214132433241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55107066216720 + 55107066216721.

It is an arithmetic number, because the mean of its divisors is an integer number (55107066216721).

Almost surely, 2110214132433441 is an apocalyptic number.

It is an amenable number.

110214132433441 is a deficient number, since it is larger than the sum of its proper divisors (1).

110214132433441 is an equidigital number, since it uses as much as digits as its factorization.

110214132433441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 110214132433441 its reverse (144334231412011), we get a palindrome (254548363845452).

The spelling of 110214132433441 in words is "one hundred ten trillion, two hundred fourteen billion, one hundred thirty-two million, four hundred thirty-three thousand, four hundred forty-one".