Search a number
-
+
11022019993837 is a prime number
BaseRepresentation
bin1010000001100100001110…
…0101100010000011101101
31110000200202112011021011201
42200121003211202003231
52421041044104300322
635235240204245501
72215212634064146
oct240310345420355
943020675137151
1011022019993837
11356a459a41226
1212a0184240891
1361c4ab4566c8
142a167bc3cacd
15141a94936d27
hexa06439620ed

11022019993837 has 2 divisors, whose sum is σ = 11022019993838. Its totient is φ = 11022019993836.

The previous prime is 11022019993793. The next prime is 11022019993847. The reversal of 11022019993837 is 73839991022011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6617272628836 + 4404747365001 = 2572406^2 + 2098749^2 .

It is an emirp because it is prime and its reverse (73839991022011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11022019993837 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11022019993847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511009996918 + 5511009996919.

It is an arithmetic number, because the mean of its divisors is an integer number (5511009996919).

Almost surely, 211022019993837 is an apocalyptic number.

It is an amenable number.

11022019993837 is a deficient number, since it is larger than the sum of its proper divisors (1).

11022019993837 is an equidigital number, since it uses as much as digits as its factorization.

11022019993837 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1469664, while the sum is 55.

The spelling of 11022019993837 in words is "eleven trillion, twenty-two billion, nineteen million, nine hundred ninety-three thousand, eight hundred thirty-seven".