Base | Representation |
---|---|
bin | 1010000001100100010001… |
… | …1011101111010101111111 |
3 | 1110000200210111220012220012 |
4 | 2200121010123233111333 |
5 | 2421041111224012111 |
6 | 35235241433013435 |
7 | 2215213165630244 |
oct | 240310433572577 |
9 | 43020714805805 |
10 | 11022034204031 |
11 | 356a466a67594 |
12 | 12a0188b5427b |
13 | 61c4b13906c6 |
14 | 2a167da9b5cb |
15 | 141a95ce248b |
hex | a06446ef57f |
11022034204031 has 2 divisors, whose sum is σ = 11022034204032. Its totient is φ = 11022034204030.
The previous prime is 11022034203997. The next prime is 11022034204037. The reversal of 11022034204031 is 13040243022011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11022034204031 is a prime.
It is a super-2 number, since 2×110220342040312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11022034203988 and 11022034204006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11022034204037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511017102015 + 5511017102016.
It is an arithmetic number, because the mean of its divisors is an integer number (5511017102016).
Almost surely, 211022034204031 is an apocalyptic number.
11022034204031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11022034204031 is an equidigital number, since it uses as much as digits as its factorization.
11022034204031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 11022034204031 its reverse (13040243022011), we get a palindrome (24062277226042).
The spelling of 11022034204031 in words is "eleven trillion, twenty-two billion, thirty-four million, two hundred four thousand, thirty-one".
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