Search a number
-
+
110222113133 = 1110020192103
BaseRepresentation
bin110011010100110111…
…1111111100101101101
3101112111120100111022102
41212221233333211231
53301213330110013
6122345122224445
710651256334416
oct1465157774555
9345446314272
10110222113133
1142821566a90
12194411b5125
13a5175273b2
1454988c080d
152d0186dd58
hex19a9bff96d

110222113133 has 4 divisors (see below), whose sum is σ = 120242305248. Its totient is φ = 100201921020.

The previous prime is 110222113117. The next prime is 110222113139. The reversal of 110222113133 is 331311222011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110222113133 - 24 = 110222113117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110222113139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5010096041 + ... + 5010096062.

It is an arithmetic number, because the mean of its divisors is an integer number (30060576312).

Almost surely, 2110222113133 is an apocalyptic number.

It is an amenable number.

110222113133 is a deficient number, since it is larger than the sum of its proper divisors (10020192115).

110222113133 is a wasteful number, since it uses less digits than its factorization.

110222113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10020192114.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 110222113133 its reverse (331311222011), we get a palindrome (441533335144).

The spelling of 110222113133 in words is "one hundred ten billion, two hundred twenty-two million, one hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 11 10020192103 110222113133