Base | Representation |
---|---|
bin | 110011010100110111… |
… | …1111111100101011101 |
3 | 101112111120100111021211 |
4 | 1212221233333211131 |
5 | 3301213330104432 |
6 | 122345122224421 |
7 | 10651256334364 |
oct | 1465157774535 |
9 | 345446314254 |
10 | 110222113117 |
11 | 42821566a76 |
12 | 194411b5111 |
13 | a51752739c |
14 | 54988c07db |
15 | 2d0186dd47 |
hex | 19a9bff95d |
110222113117 has 2 divisors, whose sum is σ = 110222113118. Its totient is φ = 110222113116.
The previous prime is 110222113063. The next prime is 110222113139. The reversal of 110222113117 is 711311222011.
It is an a-pointer prime, because the next prime (110222113139) can be obtained adding 110222113117 to its sum of digits (22).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98338060921 + 11884052196 = 313589^2 + 109014^2 .
It is a cyclic number.
It is not a de Polignac number, because 110222113117 - 27 = 110222112989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110222114117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55111056558 + 55111056559.
It is an arithmetic number, because the mean of its divisors is an integer number (55111056559).
Almost surely, 2110222113117 is an apocalyptic number.
It is an amenable number.
110222113117 is a deficient number, since it is larger than the sum of its proper divisors (1).
110222113117 is an equidigital number, since it uses as much as digits as its factorization.
110222113117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 22.
Adding to 110222113117 its reverse (711311222011), we get a palindrome (821533335128).
The spelling of 110222113117 in words is "one hundred ten billion, two hundred twenty-two million, one hundred thirteen thousand, one hundred seventeen".
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