Base | Representation |
---|---|
bin | 11001000011111100010110… |
… | …010111111110011110010111 |
3 | 112110021010120010120211201012 |
4 | 121003330112113332132113 |
5 | 103421334401000214312 |
6 | 1030231202101522435 |
7 | 32134166624651153 |
oct | 3103742627763627 |
9 | 473233503524635 |
10 | 110222121101207 |
11 | 32135a36971115 |
12 | 1044195141341b |
13 | 4966b9456381b |
14 | 1d30ac9cc8063 |
15 | cb21e4c37322 |
hex | 643f165fe797 |
110222121101207 has 2 divisors, whose sum is σ = 110222121101208. Its totient is φ = 110222121101206.
The previous prime is 110222121101203. The next prime is 110222121101221. The reversal of 110222121101207 is 702101121222011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110222121101207 - 22 = 110222121101203 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110222121101203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55111060550603 + 55111060550604.
It is an arithmetic number, because the mean of its divisors is an integer number (55111060550604).
Almost surely, 2110222121101207 is an apocalyptic number.
110222121101207 is a deficient number, since it is larger than the sum of its proper divisors (1).
110222121101207 is an equidigital number, since it uses as much as digits as its factorization.
110222121101207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 110222121101207 its reverse (702101121222011), we get a palindrome (812323242323218).
The spelling of 110222121101207 in words is "one hundred ten trillion, two hundred twenty-two billion, one hundred twenty-one million, one hundred one thousand, two hundred seven".
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