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110222211201983 is a prime number
BaseRepresentation
bin11001000011111100011011…
…101111101011101110111111
3112110021010210102010102201222
4121003330123233223232333
5103421340042031430413
61030231215041023555
732134202100543506
oct3103743357535677
9473233712112658
10110222211201983
1132135a82811171
1210441977624bbb
134966baa11c5aa
141d30ad7c5d83d
15cb21ecad3b08
hex643f1bbebbbf

110222211201983 has 2 divisors, whose sum is σ = 110222211201984. Its totient is φ = 110222211201982.

The previous prime is 110222211201979. The next prime is 110222211202021. The reversal of 110222211201983 is 389102112222011.

It is a weak prime.

It is an emirp because it is prime and its reverse (389102112222011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110222211201983 - 22 = 110222211201979 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110222211201943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55111105600991 + 55111105600992.

It is an arithmetic number, because the mean of its divisors is an integer number (55111105600992).

Almost surely, 2110222211201983 is an apocalyptic number.

110222211201983 is a deficient number, since it is larger than the sum of its proper divisors (1).

110222211201983 is an equidigital number, since it uses as much as digits as its factorization.

110222211201983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 35.

Adding to 110222211201983 its reverse (389102112222011), we get a palindrome (499324323423994).

The spelling of 110222211201983 in words is "one hundred ten trillion, two hundred twenty-two billion, two hundred eleven million, two hundred one thousand, nine hundred eighty-three".