11023011130031 has 2 divisors, whose sum is σ = 11023011130032. Its totient is φ = 11023011130030.

The previous prime is 11023011129979. The next prime is 11023011130111. The reversal of 11023011130031 is 13003111032011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11023011130031 is a prime.

It is a super-2 number, since 2×11023011130031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11023011129991 and 11023011130009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11023011130631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511505565015 + 5511505565016.

It is an arithmetic number, because the mean of its divisors is an integer number (5511505565016).

Almost surely, 2^{11023011130031} is an apocalyptic number.

11023011130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11023011130031 is an equidigital number, since it uses as much as digits as its factorization.

11023011130031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11023011130031 its reverse (13003111032011), we get a palindrome (24026122162042).

The spelling of 11023011130031 in words is "eleven trillion, twenty-three billion, eleven million, one hundred thirty thousand, thirty-one".