Base | Representation |
---|---|
bin | 10000000010100110111… |
… | …100010000000101001001 |
3 | 10220101021001022220020202 |
4 | 100002212330100011021 |
5 | 121030013441041022 |
6 | 2202221221101545 |
7 | 142432221100346 |
oct | 20024674200511 |
9 | 3811231286222 |
10 | 1102312440137 |
11 | 3955406a9547 |
12 | 1597762578b5 |
13 | 7cc41bb784c |
14 | 3b4d06537cd |
15 | 1da189cd592 |
hex | 100a6f10149 |
1102312440137 has 2 divisors, whose sum is σ = 1102312440138. Its totient is φ = 1102312440136.
The previous prime is 1102312440041. The next prime is 1102312440139. The reversal of 1102312440137 is 7310442132011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 958746472336 + 143565967801 = 979156^2 + 378901^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102312440137 - 228 = 1102044004681 is a prime.
Together with 1102312440139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1102312440139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551156220068 + 551156220069.
It is an arithmetic number, because the mean of its divisors is an integer number (551156220069).
Almost surely, 21102312440137 is an apocalyptic number.
It is an amenable number.
1102312440137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102312440137 is an equidigital number, since it uses as much as digits as its factorization.
1102312440137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 1102312440137 its reverse (7310442132011), we get a palindrome (8412754572148).
The spelling of 1102312440137 in words is "one trillion, one hundred two billion, three hundred twelve million, four hundred forty thousand, one hundred thirty-seven".
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