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110231252132413 is a prime number
BaseRepresentation
bin11001000100000100110110…
…101000000110001000111101
3112110022000010111020021202011
4121010010312220012020331
5103422012101021214123
61030235312123331221
732134642121306326
oct3104046650061075
9473260114207664
10110231252132413
11321398a2118aa5
121044367b380b11
1349679bb200a79
141d3131488b44d
15cb257b697e0d
hex644136a0623d

110231252132413 has 2 divisors, whose sum is σ = 110231252132414. Its totient is φ = 110231252132412.

The previous prime is 110231252132369. The next prime is 110231252132437. The reversal of 110231252132413 is 314231252132011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83639109375364 + 26592142757049 = 9145442^2 + 5156757^2 .

It is a cyclic number.

It is not a de Polignac number, because 110231252132413 - 217 = 110231252001341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110231252139413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55115626066206 + 55115626066207.

It is an arithmetic number, because the mean of its divisors is an integer number (55115626066207).

Almost surely, 2110231252132413 is an apocalyptic number.

It is an amenable number.

110231252132413 is a deficient number, since it is larger than the sum of its proper divisors (1).

110231252132413 is an equidigital number, since it uses as much as digits as its factorization.

110231252132413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

The spelling of 110231252132413 in words is "one hundred ten trillion, two hundred thirty-one billion, two hundred fifty-two million, one hundred thirty-two thousand, four hundred thirteen".