Base | Representation |
---|---|
bin | 1010000001101000011000… |
… | …0011000001101111110111 |
3 | 1110000210122020021120100201 |
4 | 2200122012003001233313 |
5 | 2421100340031201241 |
6 | 35235542555221331 |
7 | 2215252363501264 |
oct | 240320603015767 |
9 | 43023566246321 |
10 | 11023135022071 |
11 | 356a981390467 |
12 | 12a0435747847 |
13 | 61c628469823 |
14 | 2a1745d7026b |
15 | 141b0c78a931 |
hex | a06860c1bf7 |
11023135022071 has 2 divisors, whose sum is σ = 11023135022072. Its totient is φ = 11023135022070.
The previous prime is 11023135022027. The next prime is 11023135022083. The reversal of 11023135022071 is 17022053132011.
It is a strong prime.
It is an emirp because it is prime and its reverse (17022053132011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11023135022071 - 29 = 11023135021559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11023135022371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511567511035 + 5511567511036.
It is an arithmetic number, because the mean of its divisors is an integer number (5511567511036).
Almost surely, 211023135022071 is an apocalyptic number.
11023135022071 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023135022071 is an equidigital number, since it uses as much as digits as its factorization.
11023135022071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 11023135022071 its reverse (17022053132011), we get a palindrome (28045188154082).
The spelling of 11023135022071 in words is "eleven trillion, twenty-three billion, one hundred thirty-five million, twenty-two thousand, seventy-one".
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