Base | Representation |
---|---|
bin | 10000000010101000000… |
… | …011110100011100010111 |
3 | 10220101022100122001201202 |
4 | 100002220003310130113 |
5 | 121030033241420203 |
6 | 2202223131143115 |
7 | 142432536416543 |
oct | 20025003643427 |
9 | 3811270561652 |
10 | 1102331201303 |
11 | 395550253042 |
12 | 1597805a4a9b |
13 | 7cc45a56127 |
14 | 3b4d2d38a23 |
15 | 1da1a487388 |
hex | 100a80f4717 |
1102331201303 has 2 divisors, whose sum is σ = 1102331201304. Its totient is φ = 1102331201302.
The previous prime is 1102331201287. The next prime is 1102331201311. The reversal of 1102331201303 is 3031021332011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1102331201303 - 24 = 1102331201287 is a prime.
It is a super-2 number, since 2×11023312013032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102331801303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551165600651 + 551165600652.
It is an arithmetic number, because the mean of its divisors is an integer number (551165600652).
Almost surely, 21102331201303 is an apocalyptic number.
1102331201303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102331201303 is an equidigital number, since it uses as much as digits as its factorization.
1102331201303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1102331201303 its reverse (3031021332011), we get a palindrome (4133352533314).
The spelling of 1102331201303 in words is "one trillion, one hundred two billion, three hundred thirty-one million, two hundred one thousand, three hundred three".
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