Base | Representation |
---|---|
bin | 10000000010101000001… |
… | …011001011100111010001 |
3 | 10220101022111021010002001 |
4 | 100002220023023213101 |
5 | 121030034240144332 |
6 | 2202223240354001 |
7 | 142432562005243 |
oct | 20025013134721 |
9 | 3811274233061 |
10 | 1102333131217 |
11 | 39555135100a |
12 | 159781175901 |
13 | 7cc462806a6 |
14 | 3b4d32bc093 |
15 | 1da1a7190e7 |
hex | 100a82cb9d1 |
1102333131217 has 2 divisors, whose sum is σ = 1102333131218. Its totient is φ = 1102333131216.
The previous prime is 1102333131197. The next prime is 1102333131233. The reversal of 1102333131217 is 7121313332011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1052232814656 + 50100316561 = 1025784^2 + 223831^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1102333131217 is a prime.
It is not a weakly prime, because it can be changed into another prime (1102333131257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551166565608 + 551166565609.
It is an arithmetic number, because the mean of its divisors is an integer number (551166565609).
Almost surely, 21102333131217 is an apocalyptic number.
It is an amenable number.
1102333131217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102333131217 is an equidigital number, since it uses as much as digits as its factorization.
1102333131217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 1102333131217 its reverse (7121313332011), we get a palindrome (8223646463228).
The spelling of 1102333131217 in words is "one trillion, one hundred two billion, three hundred thirty-three million, one hundred thirty-one thousand, two hundred seventeen".
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