1102333131257 has 2 divisors, whose sum is σ = 1102333131258. Its totient is φ = 1102333131256.

The previous prime is 1102333131233. The next prime is 1102333131259. The reversal of 1102333131257 is 7521313332011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1099668919801 + 2664211456 = 1048651^2 + 51616^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1102333131257 is a prime.

Together with 1102333131259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1102333131259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551166565628 + 551166565629.

It is an arithmetic number, because the mean of its divisors is an integer number (551166565629).

Almost surely, 2^{1102333131257} is an apocalyptic number.

It is an amenable number.

1102333131257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102333131257 is an equidigital number, since it uses as much as digits as its factorization.

1102333131257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11340, while the sum is 32.

Adding to 1102333131257 its reverse (7521313332011), we get a palindrome (8623646463268).

The spelling of 1102333131257 in words is "one trillion, one hundred two billion, three hundred thirty-three million, one hundred thirty-one thousand, two hundred fifty-seven".