Base | Representation |
---|---|
bin | 10000000010101000110… |
… | …110101000000101000011 |
3 | 10220101100021200201112221 |
4 | 100002220312220011003 |
5 | 121030100144120003 |
6 | 2202224324431511 |
7 | 142433060550556 |
oct | 20025066500503 |
9 | 3811307621487 |
10 | 1102344520003 |
11 | 39555781a631 |
12 | 159784b48597 |
13 | 7cc4873a40c |
14 | 3b4d4a0469d |
15 | 1da1b7187bd |
hex | 100a8da8143 |
1102344520003 has 2 divisors, whose sum is σ = 1102344520004. Its totient is φ = 1102344520002.
The previous prime is 1102344519977. The next prime is 1102344520019. The reversal of 1102344520003 is 3000254432011.
It is a strong prime.
It is an emirp because it is prime and its reverse (3000254432011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1102344520003 - 217 = 1102344388931 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1102344520003.
It is not a weakly prime, because it can be changed into another prime (1102344520033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551172260001 + 551172260002.
It is an arithmetic number, because the mean of its divisors is an integer number (551172260002).
Almost surely, 21102344520003 is an apocalyptic number.
1102344520003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102344520003 is an equidigital number, since it uses as much as digits as its factorization.
1102344520003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1102344520003 its reverse (3000254432011), we get a palindrome (4102598952014).
The spelling of 1102344520003 in words is "one trillion, one hundred two billion, three hundred forty-four million, five hundred twenty thousand, three".
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