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1102344520003 is a prime number
BaseRepresentation
bin10000000010101000110…
…110101000000101000011
310220101100021200201112221
4100002220312220011003
5121030100144120003
62202224324431511
7142433060550556
oct20025066500503
93811307621487
101102344520003
1139555781a631
12159784b48597
137cc4873a40c
143b4d4a0469d
151da1b7187bd
hex100a8da8143

1102344520003 has 2 divisors, whose sum is σ = 1102344520004. Its totient is φ = 1102344520002.

The previous prime is 1102344519977. The next prime is 1102344520019. The reversal of 1102344520003 is 3000254432011.

It is a strong prime.

It is an emirp because it is prime and its reverse (3000254432011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1102344520003 - 217 = 1102344388931 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1102344520003.

It is not a weakly prime, because it can be changed into another prime (1102344520033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551172260001 + 551172260002.

It is an arithmetic number, because the mean of its divisors is an integer number (551172260002).

Almost surely, 21102344520003 is an apocalyptic number.

1102344520003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102344520003 is an equidigital number, since it uses as much as digits as its factorization.

1102344520003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1102344520003 its reverse (3000254432011), we get a palindrome (4102598952014).

The spelling of 1102344520003 in words is "one trillion, one hundred two billion, three hundred forty-four million, five hundred twenty thousand, three".