Base | Representation |
---|---|
bin | 1010000001101100000011… |
… | …1111110011101111110011 |
3 | 1110000220012011021120201110 |
4 | 2200123000333303233303 |
5 | 2421104401223042120 |
6 | 35240225045204403 |
7 | 2215316033116140 |
oct | 240330077635763 |
9 | 43026164246643 |
10 | 11024124034035 |
11 | 3570339689822 |
12 | 12a0670a00703 |
13 | 61c75532a4c8 |
14 | 2a17db45b3c7 |
15 | 141b694eb2e0 |
hex | a06c0ff3bf3 |
11024124034035 has 32 divisors (see below), whose sum is σ = 21344186368512. Its totient is φ = 4743152524800.
The previous prime is 11024124033983. The next prime is 11024124034043. The reversal of 11024124034035 is 53043042142011.
It is not a de Polignac number, because 11024124034035 - 27 = 11024124033907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11024124033993 and 11024124034011.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3087988141 + ... + 3087991710.
It is an arithmetic number, because the mean of its divisors is an integer number (667005824016).
Almost surely, 211024124034035 is an apocalyptic number.
11024124034035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11024124034035 is a deficient number, since it is larger than the sum of its proper divisors (10320062334477).
11024124034035 is a wasteful number, since it uses less digits than its factorization.
11024124034035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6175979883.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 11024124034035 its reverse (53043042142011), we get a palindrome (64067166176046).
The spelling of 11024124034035 in words is "eleven trillion, twenty-four billion, one hundred twenty-four million, thirty-four thousand, thirty-five".
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