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11025305403283 is a prime number
BaseRepresentation
bin1010000001110000011101…
…1010010111111110010011
31110001000020111020100200001
42200130013122113332103
52421114311140401113
635240542210110431
72215360226440303
oct240340732277623
943030214210601
1011025305403283
11357089551aa46
1212a094057b417
1361c8b2cca872
142a18b02db603
15141bd80a67dd
hexa0707697f93

11025305403283 has 2 divisors, whose sum is σ = 11025305403284. Its totient is φ = 11025305403282.

The previous prime is 11025305403253. The next prime is 11025305403317. The reversal of 11025305403283 is 38230450352011.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (38230450352011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11025305403283 - 25 = 11025305403251 is a prime.

It is a super-2 number, since 2×110253054032832 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11025305403223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5512652701641 + 5512652701642.

It is an arithmetic number, because the mean of its divisors is an integer number (5512652701642).

Almost surely, 211025305403283 is an apocalyptic number.

11025305403283 is a deficient number, since it is larger than the sum of its proper divisors (1).

11025305403283 is an equidigital number, since it uses as much as digits as its factorization.

11025305403283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 11025305403283 its reverse (38230450352011), we get a palindrome (49255755755294).

The spelling of 11025305403283 in words is "eleven trillion, twenty-five billion, three hundred five million, four hundred three thousand, two hundred eighty-three".