Base | Representation |
---|---|
bin | 10000000010110100111… |
… | …101101111100001111001 |
3 | 10220101212110000221201221 |
4 | 100002310331233201321 |
5 | 121031004203241441 |
6 | 2202300423512041 |
7 | 142441105631452 |
oct | 20026475574171 |
9 | 3811773027657 |
10 | 1102547712121 |
11 | 3956514928a9 |
12 | 159820bb8621 |
13 | 7cc7b87163b |
14 | 3b5139b8129 |
15 | 1da2e4a38d1 |
hex | 100b4f6f879 |
1102547712121 has 2 divisors, whose sum is σ = 1102547712122. Its totient is φ = 1102547712120.
The previous prime is 1102547711939. The next prime is 1102547712137. The reversal of 1102547712121 is 1212177452011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 785330943721 + 317216768400 = 886189^2 + 563220^2 .
It is a cyclic number.
It is not a de Polignac number, because 1102547712121 - 221 = 1102545614969 is a prime.
It is a super-2 number, since 2×11025477121212 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1102547712521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551273856060 + 551273856061.
It is an arithmetic number, because the mean of its divisors is an integer number (551273856061).
Almost surely, 21102547712121 is an apocalyptic number.
It is an amenable number.
1102547712121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102547712121 is an equidigital number, since it uses as much as digits as its factorization.
1102547712121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7840, while the sum is 34.
The spelling of 1102547712121 in words is "one trillion, one hundred two billion, five hundred forty-seven million, seven hundred twelve thousand, one hundred twenty-one".
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