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11031103300003 is a prime number
BaseRepresentation
bin1010000010000110000011…
…1111100110000110100011
31110001120012120000000202121
42200201200333212012203
52421213144421100003
635243341403125111
72215654010651263
oct240414077460643
943046176000677
1011031103300003
1135732a0261626
1212a1a9a213797
136202c8253b97
142a1ca033b7a3
15141e270bbcbd
hexa0860fe61a3

11031103300003 has 2 divisors, whose sum is σ = 11031103300004. Its totient is φ = 11031103300002.

The previous prime is 11031103299989. The next prime is 11031103300039. The reversal of 11031103300003 is 30000330113011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11031103300003 - 213 = 11031103291811 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11031103300003.

It is not a weakly prime, because it can be changed into another prime (11031103309003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515551650001 + 5515551650002.

It is an arithmetic number, because the mean of its divisors is an integer number (5515551650002).

Almost surely, 211031103300003 is an apocalyptic number.

11031103300003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11031103300003 is an equidigital number, since it uses as much as digits as its factorization.

11031103300003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 11031103300003 its reverse (30000330113011), we get a palindrome (41031433413014).

The spelling of 11031103300003 in words is "eleven trillion, thirty-one billion, one hundred three million, three hundred thousand, three".