Base | Representation |
---|---|
bin | 1010000010000110000011… |
… | …1111100110000111000111 |
3 | 1110001120012120000000210221 |
4 | 2200201200333212013013 |
5 | 2421213144421100124 |
6 | 35243341403125211 |
7 | 2215654010651344 |
oct | 240414077460707 |
9 | 43046176000727 |
10 | 11031103300039 |
11 | 35732a0261659 |
12 | 12a1a9a213807 |
13 | 6202c8253bc4 |
14 | 2a1ca033b7cb |
15 | 141e270bbce4 |
hex | a0860fe61c7 |
11031103300039 has 2 divisors, whose sum is σ = 11031103300040. Its totient is φ = 11031103300038.
The previous prime is 11031103300003. The next prime is 11031103300099. The reversal of 11031103300039 is 93000330113011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11031103300039 - 233 = 11022513365447 is a prime.
It is a super-2 number, since 2×110311033000392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11031103299986 and 11031103300022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11031103300099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515551650019 + 5515551650020.
It is an arithmetic number, because the mean of its divisors is an integer number (5515551650020).
Almost surely, 211031103300039 is an apocalyptic number.
11031103300039 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031103300039 is an equidigital number, since it uses as much as digits as its factorization.
11031103300039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The spelling of 11031103300039 in words is "eleven trillion, thirty-one billion, one hundred three million, three hundred thousand, thirty-nine".
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