Base | Representation |
---|---|
bin | 1010000010000110011101… |
… | …0111110100001000011111 |
3 | 1110001120111000100210221011 |
4 | 2200201213113310020133 |
5 | 2421213404314442343 |
6 | 35243400144520051 |
7 | 2215656450360253 |
oct | 240414727641037 |
9 | 43046430323834 |
10 | 11031210312223 |
11 | 3573345702482 |
12 | 12a1b0a020027 |
13 | 62031448131a |
14 | 2a1cb0636263 |
15 | 141e316a929d |
hex | a08675f421f |
11031210312223 has 2 divisors, whose sum is σ = 11031210312224. Its totient is φ = 11031210312222.
The previous prime is 11031210312193. The next prime is 11031210312247. The reversal of 11031210312223 is 32221301213011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11031210312223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11031210312194 and 11031210312203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11031210312293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515605156111 + 5515605156112.
It is an arithmetic number, because the mean of its divisors is an integer number (5515605156112).
Almost surely, 211031210312223 is an apocalyptic number.
11031210312223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031210312223 is an equidigital number, since it uses as much as digits as its factorization.
11031210312223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11031210312223 its reverse (32221301213011), we get a palindrome (43252511525234).
The spelling of 11031210312223 in words is "eleven trillion, thirty-one billion, two hundred ten million, three hundred twelve thousand, two hundred twenty-three".
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