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11031231311 is a prime number
BaseRepresentation
bin10100100011000001…
…10011101101001111
31001110210012121112122
422101200303231033
5140042443400221
65022341323155
7540235630142
oct122140635517
931423177478
1011031231311
11475092a3a1
12217a4064bb
13106a540c09
147690c0059
154486aceab
hex291833b4f

11031231311 has 2 divisors, whose sum is σ = 11031231312. Its totient is φ = 11031231310.

The previous prime is 11031231271. The next prime is 11031231347. The reversal of 11031231311 is 11313213011.

11031231311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11031231311 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11031231311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11031131311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515615655 + 5515615656.

It is an arithmetic number, because the mean of its divisors is an integer number (5515615656).

Almost surely, 211031231311 is an apocalyptic number.

11031231311 is a deficient number, since it is larger than the sum of its proper divisors (1).

11031231311 is an equidigital number, since it uses as much as digits as its factorization.

11031231311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11031231311 its reverse (11313213011), we get a palindrome (22344444322).

The spelling of 11031231311 in words is "eleven billion, thirty-one million, two hundred thirty-one thousand, three hundred eleven".