Search a number
-
+
11031233503102 = 25515616751551
BaseRepresentation
bin1010000010000110100011…
…0000010001111101111110
31110001120112122000000211121
42200201220300101331332
52421213431234044402
635243402333541154
72215660151446201
oct240415060217576
943046478000747
1011031233503102
11357335780209a
1212a1b159447ba
13620319210c37
142a1cb3751938
15141e3373a837
hexa0868c11f7e

11031233503102 has 4 divisors (see below), whose sum is σ = 16546850254656. Its totient is φ = 5515616751550.

The previous prime is 11031233503061. The next prime is 11031233503109. The reversal of 11031233503102 is 20130533213011.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×110312335031022 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11031233503109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2757808375774 + ... + 2757808375777.

It is an arithmetic number, because the mean of its divisors is an integer number (4136712563664).

Almost surely, 211031233503102 is an apocalyptic number.

11031233503102 is a deficient number, since it is larger than the sum of its proper divisors (5515616751554).

11031233503102 is an equidigital number, since it uses as much as digits as its factorization.

11031233503102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5515616751553.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 11031233503102 its reverse (20130533213011), we get a palindrome (31161766716113).

The spelling of 11031233503102 in words is "eleven trillion, thirty-one billion, two hundred thirty-three million, five hundred three thousand, one hundred two".

Divisors: 1 2 5515616751551 11031233503102