Base | Representation |
---|---|
bin | 10100100011000010… |
… | …11111010110000101 |
3 | 1001110210112200201201 |
4 | 22101201133112011 |
5 | 140043020110203 |
6 | 5022345222501 |
7 | 540240303226 |
oct | 122141372605 |
9 | 31423480651 |
10 | 11031410053 |
11 | 4750a41714 |
12 | 217a491a31 |
13 | 106a5a4391 |
14 | 76912924d |
15 | 4486e5e1d |
hex | 29185f585 |
11031410053 has 2 divisors, whose sum is σ = 11031410054. Its totient is φ = 11031410052.
The previous prime is 11031410023. The next prime is 11031410057. The reversal of 11031410053 is 35001413011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10280540449 + 750869604 = 101393^2 + 27402^2 .
It is a cyclic number.
It is not a de Polignac number, because 11031410053 - 213 = 11031401861 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11031410053.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11031410057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515705026 + 5515705027.
It is an arithmetic number, because the mean of its divisors is an integer number (5515705027).
Almost surely, 211031410053 is an apocalyptic number.
It is an amenable number.
11031410053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031410053 is an equidigital number, since it uses as much as digits as its factorization.
11031410053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 11031410053 its reverse (35001413011), we get a palindrome (46032823064).
The spelling of 11031410053 in words is "eleven billion, thirty-one million, four hundred ten thousand, fifty-three".
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