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110320046089457 is a prime number
BaseRepresentation
bin11001000101010111100011…
…001010001010010011110001
3112110121111022200201122221212
4121011113203022022103301
5103424440423244330312
61030344155102125505
732144234404425551
oct3105274312122361
9473544280648855
10110320046089457
1132173517a86176
1210458920280895
13497319c1c4159
141d35739525161
15cb4a26be3822
hex6455e328a4f1

110320046089457 has 2 divisors, whose sum is σ = 110320046089458. Its totient is φ = 110320046089456.

The previous prime is 110320046089417. The next prime is 110320046089499. The reversal of 110320046089457 is 754980640023011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101107127481616 + 9212918607841 = 10055204^2 + 3035279^2 .

It is a cyclic number.

It is not a de Polignac number, because 110320046089457 - 246 = 39951301911793 is a prime.

It is a super-3 number, since 3×1103200460894573 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (110320046089417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55160023044728 + 55160023044729.

It is an arithmetic number, because the mean of its divisors is an integer number (55160023044729).

It is a 1-persistent number, because it is pandigital, but 2⋅110320046089457 = 220640092178914 is not.

Almost surely, 2110320046089457 is an apocalyptic number.

It is an amenable number.

110320046089457 is a deficient number, since it is larger than the sum of its proper divisors (1).

110320046089457 is an equidigital number, since it uses as much as digits as its factorization.

110320046089457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 110320046089457 in words is "one hundred ten trillion, three hundred twenty billion, forty-six million, eighty-nine thousand, four hundred fifty-seven".