1103300000113 has 2 divisors, whose sum is σ = 1103300000114. Its totient is φ = 1103300000112.

The previous prime is 1103300000107. The next prime is 1103300000123. The reversal of 1103300000113 is 3110000033011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1041801951969 + 61498048144 = 1020687^2 + 247988^2 .

It is an emirp because it is prime and its reverse (3110000033011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1103300000113 - 2¹⁷ = 1103299869041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1103300000093 and 1103300000102.

It is not a weakly prime, because it can be changed into another prime (1103300000123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551650000056 + 551650000057.

It is an arithmetic number, because the mean of its divisors is an integer number (551650000057).

Almost surely, 2^{1103300000113} is an apocalyptic number.

It is an amenable number.

1103300000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103300000113 is an equidigital number, since it uses as much as digits as its factorization.

1103300000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 1103300000113 its reverse (3110000033011), we get a palindrome (4213300033124).

The spelling of 1103300000113 in words is "one trillion, one hundred three billion, three hundred million, one hundred thirteen", and thus it is an aban number.