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11033000053 is a prime number
BaseRepresentation
bin10100100011001111…
…00011100001110101
31001110220112110210121
422101213203201311
5140043422000203
65022443251541
7540256644625
oct122147434165
931426473717
1011033000053
114751928269
12217ab19bb1
13106aa0ccca
14769420885
1544890c0bd
hex2919e3875

11033000053 has 2 divisors, whose sum is σ = 11033000054. Its totient is φ = 11033000052.

The previous prime is 11032999997. The next prime is 11033000117. The reversal of 11033000053 is 35000033011.

11033000053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11008626084 + 24373969 = 104922^2 + 4937^2 .

It is a cyclic number.

It is not a de Polignac number, because 11033000053 - 213 = 11032991861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11033000353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516500026 + 5516500027.

It is an arithmetic number, because the mean of its divisors is an integer number (5516500027).

Almost surely, 211033000053 is an apocalyptic number.

It is an amenable number.

11033000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11033000053 is an equidigital number, since it uses as much as digits as its factorization.

11033000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 16.

Adding to 11033000053 its reverse (35000033011), we get a palindrome (46033033064).

The spelling of 11033000053 in words is "eleven billion, thirty-three million, fifty-three", and thus it is an aban number and an uban number.